Question
Find the currents through the resistances in the circuits shown in figure.
✓
Answer
- Since both the diodes are forward biased net resistance = 0
$\text{i}=\frac{2\text{V}}{2\Omega}=1\text{A}$
- One of the diodes is forward biased and other is reverse biase.
$\text{i}=\frac{2}{2+\infty}=0\text{A}$
Both are forward biased.
Thus the resistance is 0.
$\text{i}=\frac{2}{2}=1\text{A}.$
One is forward biased and other is reverse biased.
Thus the current passes through the forward biased diode.
$\therefore\text{i}=\frac{2}{2}=1\text{A}.$
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