Question
Find the difference:
$\frac{1}{2}-\frac{3}{8}$
$\frac{1}{2}-\frac{3}{8}$
✓
Answer
L.C.M of 2 and 8 = (2 × 2 × 2) = 8
Now, we have:
$\frac{1}{2}=\frac{1\times4}{2\times4}=\frac{4}{8}$
Therefore,
$\frac{1}{2}-\frac{3}{8}$
$=\frac{4}{8}-\frac{3}{8}$
$=\frac{(4-3)}{8}$
$=\frac{1}{8}$
Now, we have:
$\frac{1}{2}=\frac{1\times4}{2\times4}=\frac{4}{8}$
Therefore,
$\frac{1}{2}-\frac{3}{8}$
$=\frac{4}{8}-\frac{3}{8}$
$=\frac{(4-3)}{8}$
$=\frac{1}{8}$
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