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Question Bank [2022] — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsQuestion Bank [2022]4 Marks
Question
Find the differential equation from the relation $x^2 + 4y^2 = 4b^2$
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Answer

$x^2+4 y^2=4 b^2\ldots(i)$
Here, b is an arbitrary constant.
Differentiating w.r.t. $x$, we get
$ 2 x+4\left(2 y \frac{ d y}{ d x}\right)=0$
$\therefore x+4 y \frac{ d y}{ d x}=0 $

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