Question
Find the distance between parallel lines 4x – 3y + 5 = 0 and 4xr – 3y + 7 = 0.
Here, a = 4, b = – 3, c1 = 5 and c2 = 7
∴ Distance between the parallel lines
$\begin{aligned} & =\left|\frac{c_1-c_2}{\sqrt{a^2+b^2}}\right|=\left|\frac{5-7}{\sqrt{4^2+(-3)^2}}\right| \\ & =\left|\frac{-2}{\sqrt{16+9}}\right|=\left|\frac{-2}{5}\right|=\frac{2}{5} \text { units }\end{aligned}$
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