Question
Find the distance between parallel lines. l(x + y) + p = 0 and l(x + y) - r = 0

Answer

We have the equation,
$\mathrm{l} x+\mathrm{l} y+\mathrm{p}=0$
$\text { and } \mathrm{l} x+\mathrm{l} y-\mathrm{r}=0$
$\text { where } \mathrm{a}=1, \mathrm{~b}=1, \mathrm{c}_1=\mathrm{p} \text { and } \mathrm{c}_2=-\mathrm{r}$
$\therefore$ The distance between two parallel lines
d = $\frac{{\left| {{c_1} - {c_2}} \right|}}{{\sqrt {{a^2} + {b^2}} }}$
$\Rightarrow \frac{{\left| {p + r} \right|}}{{\sqrt {{1^2} + {1^2}} }}$
$\Rightarrow \frac{1}{{\sqrt 2 }}\left| {\frac{{p + r}}{1}} \right|$ units

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