Question
Find the domain of the following function:

$\text{f(x)}=\sin^{-1}\sqrt{\text{x}^2-1}$

Answer

To the domain of sin-1y which is [-1, 1]

$\therefore$ x2 -1 $\in$ [0, 1] as square root can not be negative

⇒ x2 $\in$ [1, 2]

$\Rightarrow\text{x}\in\big[-\sqrt2,-1\big]\cup\big[1,\sqrt2\big]$

Hence, the domain is $\big[-\sqrt2,-1\big]\cup\big[1,\sqrt2\big]$

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