Question
Find the equation of a circle with centre at origin and radius 4.
$x^2+y^2=r^2$
Here, r = 4
$\therefore$ The required equation of the circle is $\mathrm{x}^2+\mathrm{y}^2=4^2$ i.e., $\mathrm{x}^2+\mathrm{y}^2=16$.
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$(a+b)^2+\left(a \omega+b \omega^2\right)^2+\left(a \omega^2+b \omega\right)^2=6 a b$