The Straight Lines — MATHS STD 11 Science — Question
Gujarat BoardEnglish MediumSTD 11 ScienceMATHSThe Straight Lines2 Marks
Question
Find the equation of a line passing through the point (2, 3) and parallel to the line 3x - 4y + 5 = 0.
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Answer
Equation of a line through (2, 3) is $y - y_1 = m(x - x_1)$ ...(1) $(2, 3)$ is $(x_1y_1)$ Since the line is parallel to 3x - 4y + 5 = 0 ⇒ The slope will be equal Slope of 3x - 4y + 5 = 0 $4\text{y} = 3\text{x} + 5$ $\text{y}=\frac{3}{4}\text{x}+\frac{5}{4}$ $\Rightarrow\text{m}=\frac{3}{4}$ Substituting m and ($x_1y_1$) is (1) $\text{y}-3=\frac{3}{4}(\text{x}-2)$ $4\text{y} -12= 3\text{x} -6$ $3\text{x}-4\text{y} =-12+6=-6$ $3\text{x}-4\text{y}+6=0$
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