Question
Find the equation of the circle with centre (0, 2) and radius 2

Answer

Here $h=0, k=2$ and $r=2$
The equation of circle is
$(x-h)^2+(y-k)^2=r^2$
$\therefore(x-0)^2+(y-2)^2=(2)^2$
$\Rightarrow x^2+y^2+4-4 y=4$
$x^2+y^2-4 y=0$
Which is required equation of circle.

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