Question
Two unbisased dice are thrown, find the probability that the total of the numbers on the dice is greater than 10.

Answer

$\because$ Two dice are thrown $\because\text{n}\text{(S)} = 6^2 = 36$ Let E be the event of getting that of the numbers on the dice is greater than 10 $\therefore\text{E} = \big\{\text{(5, 6), (6, 5), (6, 6)}\big\}$ $\therefore\text{n(E)=3}$ $\therefore\text{p(E)}=\frac{3}{36}=\frac{1}{12}$ $\therefore\text{p(E)}=\frac{1}{36}$

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