Question
Find the equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2).

Answer

The slope of line joining (3, 4) and (-1, 2) is $\frac{2-4}{-1-3}=\frac{-2}{-4}=\frac{1}{2}$ The required line is $\perp$ to the given line $\therefore$ (Slope of required line) $\times\frac{1}{2}=-1 \big[\because\text{m}_1\times\text{m}_2$ for perpendicular lines$\big]$ $\text{m}_1=-2$ And the line passes through the mid point of line joining (3, 4) and (1, 2) i.e; $\Big(\frac{3-1}{2},\frac{4+2}{2}\Big)$ or $(1,3)$ $\therefore$ equation of the required line is y - 3 = (-2)(x - 1) or y - 3 = -2x + 2 or 2x + y - 5 = 0

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