Question
Find the equivalent resistance between points $A$ and $B$
✓
Answer
As shown in the circuit diagram all the 3Ω resistors re connected in parallel.
$\frac{1}{R_1}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}$
$R_1=1 \Omega$
Resistors $4\Omega$ and $6\Omega $ are connected in parallel.
$\frac{1}{R_2}=\frac{1}{4}+\frac{1}{6}=\frac{5}{12}$
$R_2=\frac{12}{5} \Omega$
Now $R_1, R_2$ and $5\Omega $ are connected in series
$R_{A B}=1+\frac{12}{5}+5$
$R_{A B}=\frac{42}{5}$
$R_{A B}=8.4 \Omega$
$\frac{1}{R_1}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}$
$R_1=1 \Omega$
Resistors $4\Omega$ and $6\Omega $ are connected in parallel.
$\frac{1}{R_2}=\frac{1}{4}+\frac{1}{6}=\frac{5}{12}$
$R_2=\frac{12}{5} \Omega$
Now $R_1, R_2$ and $5\Omega $ are connected in series
$R_{A B}=1+\frac{12}{5}+5$
$R_{A B}=\frac{42}{5}$
$R_{A B}=8.4 \Omega$
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