Question
Find the following product:
$9 t^2\left(t+7 t^3\right)$

Answer

$=9 t^2 \times t+9 t^2 \times 7 t^3$
$=9 \times t^2 \times t+9 \times 7 \times t^2 \times t^3$
$=9 \times t^{(2+1)}+63 \times t^{(2+3)}$
$=9 t^3+63 t^5$

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