Question
Find the following product:
$\left(9 x^2-x+15\right)(x 2-3)$
$\left(9 x^2-x+15\right)(x 2-3)$
✓
Answer
By column method:
$9 x^2-x+15$
$\frac{\times\left(x^2-3\right)}{9 x^4-x^3+15 x^2}$
$-27 x^2+3 x-45$
$9 x^4-x^3-12 x^2+3 x-45$
$\therefore\left(9 x^2-x+15\right)\left(x^2-3\right)$
$=9 x^4-x^3-12 x^2+3 x-45$
$9 x^2-x+15$
$\frac{\times\left(x^2-3\right)}{9 x^4-x^3+15 x^2}$
$-27 x^2+3 x-45$
$9 x^4-x^3-12 x^2+3 x-45$
$\therefore\left(9 x^2-x+15\right)\left(x^2-3\right)$
$=9 x^4-x^3-12 x^2+3 x-45$
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