Question
Find the following products:
$\left(6 x^2-x+8\right) \times\left(x^2-3\right)$

Answer

$\left(6 x^2-x+8\right) \times\left(x^2-3\right)$
$=6 x^4-18 x^2-x^3+3 x+8 x^2-24$
$=6 x^4-x^3-18 x^2+8 x^2+3 x-24$
$=6 x^4-x^3-10 x^2+3 x-24$

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