Question
Find the following products:
$\left(z^2+2\right)\left(z^2-3\right)$

Answer

Here, we will use the identity $(x+a)(x-b)=x^2+(a-b) x-a b$.
$\left(z^2+2\right)\left(z^2-3\right)$
$=\left(z^2\right) 2+(2-3)\left(z^2\right)-2 \times 3$
$=z^4-z^2-6$

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