Question
Find the general solution of :$\cos \theta=\frac{1}{\sqrt{2}}$
$
\therefore \quad \cos \theta=\cos \frac{\pi}{4}
$
The general solution of $\cos \theta=\cos \alpha$ is $\theta=2 n \pi \pm \alpha$, where $n \in Z$.
$\therefore \quad$ The general solution of $\cos \theta=\cos \frac{\pi}{4}$ is $\theta=2 n \pi \pm \frac{\pi}{4}$, where $n \in Z$.
$\therefore \quad$ The general solution of $\cos \theta=\frac{1}{\sqrt{2}}$ is $\theta=2 n \pi \pm \frac{\pi}{4}$, where $n \in Z$.
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