Question
Find the general solutions of the following equations: $\sin3\text{x}+\cos2\text{x}=0$

Answer

$\cos(2\text{x})=-\sin(3\text{x})$$=-\cos(\frac{\pi}{2}-3\text{x})$
$=\cos(\frac{\pi}{2}+3\text{x})$
$\Rightarrow2\text{n}\pi+2\text{x}=\frac{\pi}{2}+3\text{x}$
$\text{x}=(4\text{m}-1)\frac{\pi}{2},\text{m}\in\text{z}$
or
$\Rightarrow2\text{n}\pi-2\text{x}=\frac{\pi}{2}+3\text{x}$
$\text{x}=(4\text{n}-1)\frac{\pi}{10},\text{n}\in\text{z}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free