Question
Find the greatest $4$-digit number which is a perfect square.
✓
Answer
Greatest number of $4$-digits $= 9999$
First finding $\sqrt9999$ by long division method.
The remainder is $198$. This shows $99^2$ is less than $9999$ by $198$.
This means if we subtract the remainder from the number, we get a perfect square.
Therefore, the greatest $4$-digit number which is a perfect square is $= 9999 – 198 = 9801$
First finding $\sqrt9999$ by long division method.
The remainder is $198$. This shows $99^2$ is less than $9999$ by $198$.
This means if we subtract the remainder from the number, we get a perfect square.
Therefore, the greatest $4$-digit number which is a perfect square is $= 9999 – 198 = 9801$
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