Question
Find the $HCF$ of the numbers in the following using the prime factorization method: $84, 98$
✓
Answer
The given numbers are $84$ and $98.$ We have:
$\begin{array}{c|c}2&84\\\hline2&42\\\hline3&21\\\hline7&7\\\hline&1\end{array}$
$\begin{array}{c|c}2&98\\\hline7&49\\\hline7&7\\\hline&1\end{array}$
$84=2\times2\times3\times7=2^2\times3\times7$
$98=2\times7\times7=2\times7^2$
$\therefore HCF$ of the given numbers $= 2 × 7 = 14$
$\begin{array}{c|c}2&84\\\hline2&42\\\hline3&21\\\hline7&7\\\hline&1\end{array}$
$\begin{array}{c|c}2&98\\\hline7&49\\\hline7&7\\\hline&1\end{array}$
$84=2\times2\times3\times7=2^2\times3\times7$
$98=2\times7\times7=2\times7^2$
$\therefore HCF$ of the given numbers $= 2 × 7 = 14$
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