Question
Find the integral of the function $\frac{{{{\sin }^3}x + {{\cos }^3}x}}{{{{\sin }^2}x{{\cos }^2}x}}$

Answer

$\int {\frac{{{{\sin }^3}x + {{\cos }^3}x}}{{{{\sin }^2}x{{\cos }^2}x}}dx} $

$= \int {\frac{{{{\sin }^3}x}}{{{{\sin }^2}x{{\cos }^2}x}} + \frac{{{{\cos }^3}x}}{{{{\sin }^2}x{{\cos }^2}x}}dx}$

$= \int {\frac{{\sin x}}{{{{\cos }^2}x}} + \frac{{\cos x}}{{{{\sin }^2}x}}dx} $

$ = \int {\frac{{\sin x}}{{\cos x\cos x}} + \frac{{\cos x}}{{\sin x\sin x}}dx} $

$ = \int {\left( {\tan x\sec x + \cot x\cos ecx} \right)dx} $

= sec x - cosecx + c

$$

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