Question
Find the largest number of $3$ digits which is a perfect square.

Answer

The largest 3 digit number is 999 .

The number whose square is 999 is 31.61 .

Thus, the square of any number greater than 31.61 will be a 4 digit number.

Therefore, the square of 31 will be the greatest 3 digit perfect square.

$31^2=31 \times 31=961$
 

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