Find the magnetic field at point $P$ due to a straight line segment $AB$ of length $6\, cm$ carrying a current of $5\, A$. (See figure) $(\mu _0 = 4p\times10^{-7}\, N-A^{-2})$
A$2.0\times10^{-5}\, T$
B$3.0\times10^{-5}\, T$
C$2.5\times10^{-5}\, T$
D$1.5\times10^{-5}\, T$
JEE MAIN 2019, Diffcult
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D$1.5\times10^{-5}\, T$
d $B=\frac{\mu_{0} I}{4 \pi d} 2 \sin \theta$
$d=4\, \mathrm{cm}$
$\sin \theta=\frac{3}{5}$
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