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Measures of dispersion — Statistics STD 11 Commerce — Question

Gujarat BoardEnglish MediumSTD 11 CommerceStatisticsMeasures of dispersion2 Marks
Question
Find the mean deviation for the observations $: 3, 8, 1, 7, 6$
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Answer

Here,$n=5$
$X: 3,8,1,7,6$
$\therefore$ Mean $\bar{x}=\frac{3+8+1+7+6}{5}=\frac{25}{5}=5$
$\sum|x-\bar{x}|=2+3+4+2+1$
Mean deviation $MD =\frac{2|x-\bar{x}|}{n}=\frac{12}{5}=2.4$

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