MCQ
Find the middle term in the expansion of $\Big(\frac{2\text{x}}{3}+\frac{3}{2\text{x}}\Big)^{10}.$
  • A
    210
  • B
    630
  • 252
  • D
    756

Answer

Correct option: C.
252
  1. 252
Solution
The middle term will be the 6th term.
It will also be the only term independent of x.
Hence the coefficient will be
$T_{5+1}​ = ^{10}C_{5​}$
$=\frac{10!}{5!(5!)}$
= 252

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