MCQ
if $x = \,\frac{4}{3}\, - \,\frac{{4x}}{9}\, + \,\,\frac{{4{x^2}}}{{27}}\, - \,\,.....\,\infty $ , then $x$ is equal to
- ✓only $1$
- B$1$ or $-4$
- Conly $-4$
- D$-1$ or $4$
$\Rightarrow 3 x+x^{2}=4$
$\Rightarrow x^{2}+3 x-4 \Rightarrow(x+4)(x-1)=0$
$\Rightarrow x=1,-4$
$\Rightarrow x=1$ only as $\left|-\frac{4}{3}\right|>1$
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