MCQ
Find the $\%$ difference (approximate) in deBorglie wavelength if the temperature of gas become double ............. $\%$
  • $30$
  • B
    $40$
  • C
    $50$
  • D
    $100$

Answer

Correct option: A.
$30$
a
$\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{m}(\mathrm{K} . \mathrm{E} .)}}=\mathrm{KE}=\frac{3}{2} \mathrm{KT}$

$\Rightarrow \lambda \propto \frac{1}{\sqrt{\mathrm{T}}} \Rightarrow \lambda_{2}=\frac{\lambda_{1}}{\sqrt{2}}$

of charge $=\frac{f-i}{\ell} \times 100=\frac{\frac{\lambda_{1}}{\sqrt{2}}-\lambda_{1}}{\lambda_{1}} \times 100$

$=\frac{\frac{1}{\sqrt{2}}-1}{1} \times 100=30 \%$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free