Question
Find the point on y-axis which is equidistant from the points (3, 1, 2) and (5, 5, 2).

Answer

Let P(0, y, 0) be a point on y-axis which is equidistant from Q(3, 1, 2) and R(5, 5, 2).

So

(PR)2 = (PQ)2 ⇒ (0 - 5)2 + (y - 5)2 + (0 - 2)2 = (0 - 3) + (y - 1)2 + (0 + 2)

⇒ 25 + y2 + 25 - 10y + 4 = 9 + y2 + 1 - 2y + 4

⇒ -10y + 2y = 14 - 54

⇒ -14z - 8z = 16 - 49

⇒ -8y = -40

⇒ y = 5

so, the required point is (0, 5, 0)

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