c (c) In steady state the branch containing capacitors, can be neglected. So reduced circuit is as follows
Power $P = \frac{{{V^2}}}{R} = \frac{{{{(2)}^2}}}{4} = 1\,W$.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
The resistance of platinum wire at $0^{\circ}\,C$ is $2\,\Omega$ and $6.8\,\Omega$ at $80^{\circ} \,C$. The temperature coefficient of resistance of the wire is :
An ammeter with internal resistance $90\,\Omega $ reads $1.85\, A$ when connected in a circuit containing a battery and two resistors $700\,\Omega $ and $410\,\Omega $ in series. Actual current will be
A potential $V_0$ is applied across a uniform wire of resistance $R$. The power dissipation is $P_1$. The wire is then cut into two equal halves and a potential of $V _0$ is applied across the length of each half. The total power dissipation across two wires is $P_2$. The ratio $P_2: P_1$ is $\sqrt{x}: 1$. The value of $x$ is $.............$.
In a potentiometer experiment shown here, for the position $X$ of the jockey $J,$ there occurs a null deflection in the galvanometer. Then the potential difference between points $A$ and $X$ is ................ $V$