Question
Find the principal value of $\cot ^{-1}\left(\frac{-1}{\sqrt{3}}\right)$.

Answer

To find principal value of $\cot ^{-1}\left(\frac{-1}{\sqrt{3}}\right)$
We have $\cot \frac{2 \pi}{3}=-\frac{1}{\sqrt{3}}$.
Where $-\frac{1}{\sqrt{3}} \in R$ and $\frac{2 \pi}{3} \in(0, \pi)$
$\therefore$ Principal value of $\cot ^{-1}\left(\frac{-1}{\sqrt{3}}\right)=\frac{2 \pi}{3}$.

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