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INVERSE TRIGNOMETRIC FUNCTIONS — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSINVERSE TRIGNOMETRIC FUNCTIONS2 Marks
Question
Find the principal values:
 $\sec^{-1}\bigg(\frac{2}{\sqrt{3}}\bigg)$
✓

Answer

$\text{Let Y} =\sec^{-1}\left(\frac{2}{\sqrt{3}}\right)$, $\sec\text{Y}= \frac{2}{\sqrt{3}} $
$\sec\text{Y}=\sec\frac{\pi}{6}$
$\text{Y}=\frac{\pi}{6}$

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