Find the principal values: ^ -1 (2 3 ) - Vidyadip

Question

Find the principal values:
$\sec^{-1}\bigg(\frac{2}{\sqrt{3}}\bigg)$

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Answer

$\text{Let Y} =\sec^{-1}\left(\frac{2}{\sqrt{3}}\right)$,

$\sec\text{Y}= \frac{2}{\sqrt{3}} $

$\sec\text{Y}=\sec\frac{\pi}{6}$

$\text{Y}=\frac{\pi}{6}$

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