Question
Find the product:
$-11 a(3 a+2 b)$
$-11 a(3 a+2 b)$
✓
Answer
To find the product, we will use distributive law as follows:
$-11 a(3 a+2 b)$
$=(-11 a) \times 3 a+(-11 a) \times 2 b$
$=(-11 \times 3) \times(a \times a)+(-11 \times 2) \times(a \times b)$
$=(-33) \times\left(a^{1+1}\right)+(-22) \times(a \times b)$
$=-33 a^2-22 a b$
Thus, the answer is $-33 a^2-22 a b$
$-11 a(3 a+2 b)$
$=(-11 a) \times 3 a+(-11 a) \times 2 b$
$=(-11 \times 3) \times(a \times a)+(-11 \times 2) \times(a \times b)$
$=(-33) \times\left(a^{1+1}\right)+(-22) \times(a \times b)$
$=-33 a^2-22 a b$
Thus, the answer is $-33 a^2-22 a b$
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