Question
Find the product:
$x y\left(x^3-y^3\right)$
$x y\left(x^3-y^3\right)$
✓
Answer
To find the product, we will use distributive law as follows:
$x y\left(x^3-y^3\right)$
$=x y \times x^3-x y \times y^3$
$=\left(x \times x^3\right) \times y-x \times\left(y \times y^3\right)$
$=x^{1+3} y-x y^{1+3}$
$=x^4 y-x y^4$
Thus, the answer is $x^4 y-x y^4$
$x y\left(x^3-y^3\right)$
$=x y \times x^3-x y \times y^3$
$=\left(x \times x^3\right) \times y-x \times\left(y \times y^3\right)$
$=x^{1+3} y-x y^{1+3}$
$=x^4 y-x y^4$
Thus, the answer is $x^4 y-x y^4$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the area, in square metres, of the trapezium whose bases and altitudes are as under:
bases $=12 dm$ and 20 dm , altitude $=10 dm$
→bases $=12 dm$ and 20 dm , altitude $=10 dm$
Find the gain or loss percent when.
CP = Rs. 80 and SP = Rs. 76.80
CP = Rs. 80 and SP = Rs. 76.80
Find the product:
$0.1 y\left(0.1 x^5+0.1 y\right)$
→$0.1 y\left(0.1 x^5+0.1 y\right)$
How many litres of water flow out of a pipe having an area of cross-section of $5 cm^2$ in one minute, if the speed of water in the pipe is $30 cm /$ sec?
→Expand : $(101)^3$
→Find the least number which must be added to 8400 to obtain a perfect square. Find this perfect square and its square root.
The pie-chart given in represents the expenditure on different items in constructing a flat in Delhi. If the expenditure incurred on cement is ₹ 112500, find the following:
- Total cost of the flat.
- Expenditure incurred on labour.
A sum of money amounts to Rs. 10240 in 2 years at $6\frac{2}{3}\%$ per annum, compounded annually. Find the sum.
→2.2 cubic dm of brass is to be drawn into a cylindrical wire 0.25cm in diameter. Find the length of the wire.
Verify the property: x × (y + z) = x × y + x × z by taking:
$\text{x}=\frac{-8}{3},\text{y}=\frac{5}{6},\text{z}=\frac{-13}{12}$
→$\text{x}=\frac{-8}{3},\text{y}=\frac{5}{6},\text{z}=\frac{-13}{12}$