Question
Find the remainder obtained on dividing $p(x) = x^3 + 1 by x + 1.$
✓
Answer
By long division,we have,
Therefore, remainder is $0.$
Here $p(x) = x^3 + 1$, and the root of $x + 1 = 0$ is $x = –1.$ We have,
$p(–1) = (–1)^3 + 1$
$= –1 + 1 = 0,$
which is equal to the remainder obtained by actual division.
Therefore, remainder is $0.$
Here $p(x) = x^3 + 1$, and the root of $x + 1 = 0$ is $x = –1.$ We have,
$p(–1) = (–1)^3 + 1$
$= –1 + 1 = 0,$
which is equal to the remainder obtained by actual division.
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