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Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsPolynomials1 Mark
Question
Find the remainder when $x^3+3 x^2+3 x+1$ is divided by $x+\pi$
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Answer

Let $\mathrm{p}(\mathrm{x})=\mathrm{x}^3+3 \mathrm{x}^2+3 \mathrm{x}+1$
$x+\pi=0$
$\Rightarrow \mathrm{x}=-\pi$
$\therefore$ Remainder $=(-\pi)^3+3(-\pi)^2+3(-\pi)+1=-\pi^3+3 \pi^2-3 \pi+1$

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