Question
Find the remaining angles in the following quadrilaterals.
Image

Answer

Here $PQ \| SR$, and $PS \| QR$
$\therefore PQRS$ is a parallelogram.
$\angle P =\angle R =110^{\circ}$ $\qquad$ (Opposite angles of a parallelogram are equal)
$\angle P +\angle S =180^{\circ}$ $\qquad$ (The sum of the adjacent angles of a parallelogram is $180^{\circ}$ )
$110^{\circ}+\angle S =180^{\circ}$
$\angle S =180^{\circ}-110^{\circ}$
$\angle S =70^{\circ}$.
$\angle S =\angle Q =70^{\circ}$ $\qquad$ (Opposite angles of a parallelogram are equal)

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