Question
Find the solution of the linear equation $x+2y = 8$ which represents a point on:
$i. x-$axis
$ii. y-$axis

Answer

We have, $x + 2y = 8 ...(i)$
$i.$ When the point is on the $X-$axis, then put $y = 0$ in Eq. $(i)$, we get
$x + 2(0) = 8$
$\Rightarrow x = 8 $
Hence, the required point is $(8, 0).$​​​​​​​
$ii.$ When the point is on the $Y-$axis, then put $x = 0$ in Eq. $(i)$, we get
$0 + 2y = 8$
$\Rightarrow \text{y}=\frac{8}{2}= 4$
Hence, the required point is $(0, 4).$

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