Question
If $f(x)=2 x^3-13 x^2+17 x+12$, Find: $f(0)$

Answer

The given polynomial is $f(x)=2 x^3-13 x^2+17 x+12 f(0)$
we need to substitute the ' $(0)^{\prime}$ in $f(x) f(0)=2(0)^3-13(0)^2+17(0)+12=$
$(2 \times 0)-(13 \times 0)+(17 \times 0)+12=0-0+0+12=12$ therefore $f(0)=12$

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