Question
Find the sum
$-2 \frac{1}{3}+4 \frac{3}{5}$

Answer

We have,$-\left(2 \frac{1}{3}\right)+\left(4 \frac{3}{5}\right)=-\left(\frac{2 \times 3+1}{3}\right)+\frac{4 \times 5+3}{5}$$=\frac{-7}{3}+\frac{23}{5}$
$\because $ LCM of 3 and $5=15$
$
\therefore
\frac{-7}{3}=\frac{-7 \times 5}{3 \times 5}=\frac{-35}{15} \text { and } \frac{23}{5}=\frac{23 \times 3}{5 \times 3}=\frac{69}{15}
$
Now, $-2 \frac{1}{3}+4 \frac{3}{5}=\frac{-35}{15}+\frac{69}{15}=\frac{-35+69}{15}$
$=\frac{34}{15}=2 \frac{4}{15}$

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