Question
Find the sum:
$3\frac{1}{8}+1\frac{5}{12}$
$3\frac{1}{8}+1\frac{5}{12}$
✓
Answer
L.C.M. of 8 and 12 = (2 × 2 × 2 × 3) = 34
$\begin{array}{c|c}2&8,12\\\hline2&4,6\\\hline2&2,3\\\hline3&1,3\\\hline&1,1\end{array} $
Therefore,
$3\frac{1}{8}+1\frac{5}{12}$
$=\frac{25}{8}+\frac{17}{12}$
$=\frac{(75+34)}{24}$
$\Big(\frac{24}{8}=3,3\times25=75\Big)$
and $\Big(\frac{24}{12}=2,2\times17=34\Big)$
$=\frac{109}{24}$
$=4\frac{13}{24}$
$\begin{array}{c|c}2&8,12\\\hline2&4,6\\\hline2&2,3\\\hline3&1,3\\\hline&1,1\end{array} $
Therefore,
$3\frac{1}{8}+1\frac{5}{12}$
$=\frac{25}{8}+\frac{17}{12}$
$=\frac{(75+34)}{24}$
$\Big(\frac{24}{8}=3,3\times25=75\Big)$
and $\Big(\frac{24}{12}=2,2\times17=34\Big)$
$=\frac{109}{24}$
$=4\frac{13}{24}$
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