Question
Find the sum:
$3\frac{2}{3}+1\frac{5}{6}+2$
$3\frac{2}{3}+1\frac{5}{6}+2$
✓
Answer
We have,
L.C.M. of 3 and 6 = (2 × 3) = 6
$\begin{array}{c|c}3&3,6\\\hline2&1,2\\\hline&1,1\end{array}$
Therefore,
$3\frac{2}{3}+1\frac{5}{6}+2$
$=\frac{11}{3}+\frac{11}{6}+\frac{2}{1}$
$=\frac{(22+11+12)}{6}$
$\Big(\frac{6}{3}=2,2\times11=22\Big)$
$\Big(\frac{6}{6}=1,1\times11=11\Big)$
and $\Big(\frac{6}{1}=6,6\times2=12\Big)$
$=\frac{45}{6}$
$=\frac{15}{2}$
$=7\frac{1}{2}$
L.C.M. of 3 and 6 = (2 × 3) = 6
$\begin{array}{c|c}3&3,6\\\hline2&1,2\\\hline&1,1\end{array}$
Therefore,
$3\frac{2}{3}+1\frac{5}{6}+2$
$=\frac{11}{3}+\frac{11}{6}+\frac{2}{1}$
$=\frac{(22+11+12)}{6}$
$\Big(\frac{6}{3}=2,2\times11=22\Big)$
$\Big(\frac{6}{6}=1,1\times11=11\Big)$
and $\Big(\frac{6}{1}=6,6\times2=12\Big)$
$=\frac{45}{6}$
$=\frac{15}{2}$
$=7\frac{1}{2}$
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