Question
Find the sum:
$34 + 32 + 30 + ..... + 10.$
$34 + 32 + 30 + ..... + 10.$
✓
Answer
$34 + 32 + 30 + ..... + 10$
$a = 34, d = -2, 1 = a_n = 10$
$10 = 34 + (n - 1) (-2)$
$+24 = 2(n - 1)$
$n - 1 = 12$
$n = 13$
$\therefore\ \text{S}_{13}=\frac{13}{2}(34+10)$
$=\frac{13}{2}\times44$
$=286$
$a = 34, d = -2, 1 = a_n = 10$
$10 = 34 + (n - 1) (-2)$
$+24 = 2(n - 1)$
$n - 1 = 12$
$n = 13$
$\therefore\ \text{S}_{13}=\frac{13}{2}(34+10)$
$=\frac{13}{2}\times44$
$=286$
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