Question
Find the sum: $\frac{8}{9}+\frac{7}{12}$
✓
Answer
$\frac{8}{9}+\frac{7}{12}$
$LCM$ of $9$ and $12 = 36$
$\therefore\frac{8}{9}=\frac{8\times4}{9\times4}=\frac{32}{36}$
$\frac{7}{12}=\frac{7\times3}{12\times3}=\frac{21}{36}$
$\therefore\frac{8}{9}+\frac{7}{12}=\frac{32}{36}=\frac{21}{36}$
$=\frac{32+21}{36}=\frac{53}{36}=1\frac{17}{36}$
$LCM$ of $9$ and $12 = 36$
$\therefore\frac{8}{9}=\frac{8\times4}{9\times4}=\frac{32}{36}$
$\frac{7}{12}=\frac{7\times3}{12\times3}=\frac{21}{36}$
$\therefore\frac{8}{9}+\frac{7}{12}=\frac{32}{36}=\frac{21}{36}$
$=\frac{32+21}{36}=\frac{53}{36}=1\frac{17}{36}$
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