Maharashtra BoardEnglish MediumSTD 10MathsP-1 Arithmetic Progression4 Marks
Question
Find the sum of first 123 even natural numbers.
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Answer
List of first 123 even natural number is
2,4,6,......
Where first term $a=2$
Second term $\mathrm{t}_1=4$
Third term $\mathrm{t}_2=6$
Thus, common difference $d=t_2-t_1=6-4=2$
$n=123$
By using sum of $\mathrm{n}^{\text {th }}$ term of an A.P. is
$S_n=\frac{n}{2}[2 a+(n-1) d]$
Where, $\mathrm{n}=$ no. of terms
$a=$ first term
$\mathrm{d}=$ common difference
$S_n=$ sum of $n$ terms
Thus, Substituting given value in formula we can find the value of $S_n$
$\Rightarrow S_n=\frac{123}{2}[2 \times 2+(123-1) \times 2] $
$ \Rightarrow S_n=\frac{123}{2}[4+122 \times 2]$
$ \Rightarrow S_n=\frac{123}{2}[4+244] $
$ \Rightarrow S_n=\frac{123}{2} \times 248=123 \times 122=15252$
Thus, $S_n$ = 15252
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