Find the sum of first 40 positive integers divisible by 6 . - Vidyadip

MCQ

Find the sum of first 40 positive integers divisible by 6 .

A
2340
B
2520
C
4950
✓
4920

✓

Answer

Correct option: D.

4920

(d) : Numbers divisible by 6 are $6,12,18, \ldots$
The series form an A.P. with first term $(a)=6$ and common difference $(d)=6$ and $n=40$
Now, sum of $n$ terms $S_n=\frac{n}{2}\{2 a+(n-1) d\}$
$
\begin{aligned}
\therefore \quad S_{40} & =\frac{40}{2}\{2 \times 6+(40-1) 6\}=20\{12+234\} \\
& =20 \times 246=4920
\end{aligned}
$

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