Question
Find the sum of odd integers from 1 to 2001.

Answer

Odd integers from 1 to 2001 are $1,3,5,7, \ldots, 2001$.
Here, $a=1, d=3-1=2$ and $a_n=2001$
$\therefore a_n=a+(n-1) d$
$\therefore 2001=1+(n-1) \times 2$
$\Rightarrow 2001-1=(n-1) \times 2$
$\Rightarrow \frac{2000}{2}=(n-1)$
$\Rightarrow n=1000+1=1001$
Now, $\mathrm{S}_{\mathrm{n}}=\frac{n}{2}(\mathrm{a}+\mathrm{I})$
$\Rightarrow S_{1001}=\frac{1001}{2}(1+2001)$
$\Rightarrow S_{1001}=\frac{1001}{2} \times 2002=1002001$

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