Question
Find the supplementary/complementary angle
✓
Answer
$\angle ABD +\angle DBC =90^{\circ}$
$\angle ABD +46^{\circ}=90^{\circ}$
$\angle ABD =90^{\circ}-46^{\circ}$
$\angle ABD =44^{\circ}$
$\angle ABD +46^{\circ}=90^{\circ}$
$\angle ABD =90^{\circ}-46^{\circ}$
$\angle ABD =44^{\circ}$
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