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Maths 2 Marks

T1 CH4 Geometry · Tamil Nadu Board STD 6 (Tamil - English Medium). 17 questions.

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17 questions · timed · auto-graded

Question 12 Marks
Which angle is equal to twice its complement?
Answer
Let the angle be $x$ According to the problem, $x=2 \times(90-x)$
$ x=180-2 x$
$x+2 x=180$
$3 x=180$
$x=\frac{180}{3}$
$x=60 $
$\therefore$ The angle is $60^{\circ}$
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Question 22 Marks
From the figure name a pair of supplementary angles
Answer
$\angle FAD , \angle DAC$
$\angle BAC , \angle CAE$
$\angle FAB , \angle BAC$
$\angle FAB , \angle FAE $
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Question 32 Marks
Find the parallel and intersecting line segments in the picture given below.
Answer
Parallel lines:
$\overline{ AB }$ and $\overline{ EF }$
$\overline{ AD }$ and $\overline{ EH }$
$\overline{ DC }$ and $\overline{ HG }$
$\overline{ BC }$ and $\overline{ FG }$
$\overline{ AE }$ and $\overline{ DH }$
$\overline{ HD }$ and $\overline{ GC }$
$\overline{ GC }$ and $\overline{ BF }$
$\overline{ BF }$ and $\overline{ AE }$
Intersecting lines:
$E F$ and $A D$
$D C$ and $F G$
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Question 42 Marks
Two complementary angles are in ratio 7 : 2. Find the angles
Answer
Total of complementary angles $=90^{\circ}$ The angles are in the ratio $7: 2$ Dividing total angles to $7+2=9$ equal parts
One angle $=\frac{7}{9} \times 90=70^{\circ}$
Another angle $=\frac{2}{9} \times 90=20^{\circ}$ Two angles are $70^{\circ}$ and $20^{\circ}$.
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Question 52 Marks
Draw any 3 lines that are not concurrent. Find the number of points of intersection
Answer

Number of points of intersection = 3
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Question 82 Marks
Name the vertex and sides from the angle.

Vertex _____________
Sides ______________
Answer
>
Vertex = D
Sides = DE and DF
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Question 92 Marks
Name the vertex and sides from the angle.
>
Vertex _____________
Sides ______________
Answer

Vertex = D
Sides = DE and DC
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Question 142 Marks
Find the supplementary/complementary angle
Answer
$\angle ABD +\angle DBC =90^{\circ}$
$\angle ABD +46^{\circ}=90^{\circ}$
$\angle ABD =90^{\circ}-46^{\circ}$
$\angle ABD =44^{\circ}$
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Question 152 Marks
Find the supplementary/complementary angle
Answer
$\angle ABD +\angle DBC =180^{\circ}$
$\angle ABD +25^{\circ}=180^{\circ}$
$\angle ABD =180^{\circ}-25^{\circ}$
$\angle ABD =155^{\circ}$
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Question 162 Marks
Find the supplementary/complementary angle
Answer
$\angle A B D+\angle D B C=90^{\circ}$
$\angle A B D+30^{\circ}=90^{\circ}$
$\angle A B D=90^{\circ}-30^{\circ}$
$\angle A B D=60^{\circ}$
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Question 172 Marks
Find the supplementary/complementary angle
Answer
$\angle CBD +\angle EBC =180^{\circ}$
$67^{\circ}+\angle EBC =180^{\circ}$
$\angle EBC =180^{\circ}-67^{\circ}$
$\angle EBC =113^{\circ}$
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2 Marks - Maths STD 6 Questions - Vidyadip