Question
Find the unknown value : ${ }^{n} C_{2}=28$

Answer

${ }^n C_2=28$
$ \therefore \frac{n !}{2 !(n-2) !}=28$
$ \therefore \frac{n(n-1)(n-2) !}{2 \times(n-2) !}=28$
$ \therefore \mathrm{n}(\mathrm{n}-1)=28 \times 2$
$ \therefore \mathrm{n}(\mathrm{n}-1)=56$
$ \therefore \mathrm{n}(\mathrm{n}-1)=8 \times 7$
$ \therefore \mathrm{n}(\mathrm{n}-1)=8(8-1)$
$ \therefore \mathrm{n}=8$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free